Description Link to heading
1144. Decrease Elements To Make Array Zigzag (Medium)
Given an array nums
of integers, a move consists of choosing any element and decreasing it by
1.
An array A
is a zigzag array if either:
- Every even-indexed element is greater than adjacent elements, ie.
A[0] > A[1] < A[2] > A[3] < A[4] > ...
- OR, every odd-indexed element is greater than adjacent elements, ie.
A[0] < A[1] > A[2] < A[3] > A[4] < ...
Return the minimum number of moves to transform the given array nums
into a zigzag array.
Example 1:
Input: nums = [1,2,3]
Output: 2
Explanation: We can decrease 2 to 0 or 3 to 1.
Example 2:
Input: nums = [9,6,1,6,2]
Output: 4
Constraints:
1 <= nums.length <= 1000
1 <= nums[i] <= 1000
Solution Link to heading
Note that element can only be decreased by 1
. Analog by case.
Code Link to heading
class Solution {
public:
int movesToMakeZigzag(vector<int> &nums) {
if (nums.size() == 1)
return 0;
int cnt2 = 0;
for (int i = 1; i < nums.size(); i += 2) {
if (i + 1 < nums.size() && i - 1 >= 0) {
int tmp = std::min(nums[i + 1], nums[i - 1]);
if (tmp <= nums[i]) {
cnt2 += nums[i] - tmp + 1;
}
} else if (i + 1 >= nums.size()) {
if (nums[i - 1] <= nums[i]) {
cnt2 += nums[i] - nums[i - 1] + 1;
}
} else {
if (nums[i + 1] <= nums[i]) {
cnt2 += nums[i] - nums[i + 1] + 1;
}
}
}
int cnt4 = 0;
for (int i = 0; i < nums.size(); i += 2) {
if (i + 1 < nums.size() && i - 1 >= 0) {
int tmp = std::min(nums[i + 1], nums[i - 1]);
if (tmp <= nums[i]) {
cnt4 += nums[i] - tmp + 1;
}
} else if (i + 1 >= nums.size()) {
if (nums[i - 1] <= nums[i]) {
cnt4 += nums[i] - nums[i - 1] + 1;
}
} else {
if (nums[i + 1] <= nums[i]) {
cnt4 += nums[i] - nums[i + 1] + 1;
}
}
}
return std::min(cnt2, cnt4);
}
};